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musicman
Rank #15915 on Subscribers Level 165 Comments: Soldier Of Funnyjunk Offline Send mail to musicman Block musicman Invite musicman to be your friend 

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#13  show your work [+] (1 new reply)  02/25/2014 on It's true too  0 
#9  Duke Nukem  12/29/2013 on as seen on tumblr  +1 
#107  not in terms of limits it is limit as the number approaches th… [+] (1 new reply)  12/27/2013 on Rated M for math  0 
#38  so no, the number never truely reach 0 or in your pictures cas… [+] (3 new replies)  12/26/2013 on Rated M for math  0 
#49 
nthmetal (12/26/2013) [] "Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and lim x−4 x→3+ x−3 X→−∞" Dude what the fuck are you trying to say. I read this and I can't even understand what the hell you're doing or where the hell these numbers came from. Like where the hell did you get x→3+, Either of the cases we have been discussing so far are either x→1, x→4, and x→5. "x→3+ x−3 X→−∞" what the hell kind of bullshit is this. Where did this second "X" variable come from, I thought we were only using x, and how the hell can x approach 3+x3X and how can that approach infinity. Buddy learn how to write math. Use a picture, jot it down legibly on a piece of paper. Pretend i'm a 5 year old if that helps you learn to write better. Either way I don't know what the hell it is you're trying to argue, but all I know is that i'm not wrong. Anon said that the limit as x approaches 4 of the function on the screen will be zero, this implys that any number divided by zero will equal ∞. This is untrue because any number over zero will be undefined.  
#33  are you stupid [+] (7 new replies)  12/26/2013 on Rated M for math  5 
#36 
nthmetal (12/26/2013) [] Anything/0 is undefined. ANYTHING. 0/0 is undefined. ∞/0 is undefined. (∞,∞)/0 is undefined. Anon said anything/0 is infinity, now I'm assuming he meant in the context of limits because he'd be even more wrong otherwise. Lets take a simple limit, the one in the picture. If we attempt to solve it by pluging in we can see that we get 1/0, which means the limit DOES NOT EXIST However, we can take the left hand limit and get that it equals ∞ or the right hand limit and it equals ∞. However we can't take the regular limit because it does not exist. Now does not existing equal infinity as annon said? NO it doesn't. The same applies to the limit on the monster. If we were to replace it with as x→4 instead of x→5 it would have no solution if you attempted to take the limit. Do you understand now you ignorant twat. #72 
zecken (12/26/2013) [] you propably never heard of Bernoulli and l'Hospital. lets say you have an equtation which would result in 0/0 it doesn t have to be undefined. lets say lim x>0 x²/x. this would be undefined in your case so but now we can, because of bernoulli, make a derviation which leaves us with lim x>0 2x/1 put in 0 and you got 0/1 which is Infinity, You will find a lot of cases where you can use Bernoulli. Sorry for my English... #38 
musicman (12/26/2013) [] so no, the number never truely reach 0 or in your pictures case 1. In the case of your picture as the limit approaches 1 you can pick a number .9999999999 which is almost 1 but never reaches 1. 1/(1.9999999999) 1/(.0000000001) or 1000000000/1 and from the left it is 1000000000 and so forth Now, how do we tell whether it's ∞, −∞, or neither? Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and lim x−4 x→3+ x−3 X→−∞ #49 
nthmetal (12/26/2013) [] "Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and lim x−4 x→3+ x−3 X→−∞" Dude what the fuck are you trying to say. I read this and I can't even understand what the hell you're doing or where the hell these numbers came from. Like where the hell did you get x→3+, Either of the cases we have been discussing so far are either x→1, x→4, and x→5. "x→3+ x−3 X→−∞" what the hell kind of bullshit is this. Where did this second "X" variable come from, I thought we were only using x, and how the hell can x approach 3+x3X and how can that approach infinity. Buddy learn how to write math. Use a picture, jot it down legibly on a piece of paper. Pretend i'm a 5 year old if that helps you learn to write better. Either way I don't know what the hell it is you're trying to argue, but all I know is that i'm not wrong. Anon said that the limit as x approaches 4 of the function on the screen will be zero, this implys that any number divided by zero will equal ∞. This is untrue because any number over zero will be undefined.  
#25  sounds like a weird threesome  05/24/2013 on How we grow up.....  1 
#64  If this was trure dobby never would have died  05/14/2013 on What if?  0 
#26  8/10 would bang  05/08/2013 on Where is your god now?  0 
#32  pics? [+] (1 new reply)  04/28/2013 on Wat  0 
 
#126  http://www . poopsenders . com/  04/28/2013 on sounds about right  +2 
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