masterofallgoats
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Level 215 Comments: Comedic Genius Offline
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Although wolfram is an excellent tool, do not become fully dependent on it because it can't help on a test.
((x3)(2x^(3/5)  x^(7/3))/(x3)) in the denominator. I'm not sure how to simplify the denominator from there and I'm not really sure what I'd end up with if I plugged in ∞ for x.
Just help me understand how you worked it out.
1.)www.wolframalpha.com/
Wolfram Alpha for checking them answers. It even shows the steps on how to solve
2.)www.khanacademy.org/
Khan academy if you want a good teacher
Although wolfram is an excellent tool, do not become fully dependent on it because it can't help on a test.
Evaluate:
lim x>∞ F(x) = ((2x^(3/5)  x^(7/3))/(x3))
What's your take?
((x3)(2x^(3/5)  x^(7/3))/(x3)) in the denominator. I'm not sure how to simplify the denominator from there and I'm not really sure what I'd end up with if I plugged in ∞ for x.
Just help me understand how you worked it out.
You have to go to Options>Game options and then turn the options at the botton on Debug.