Rank #884 on CommentsLevel 348 Comments: Sold Soul
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|Date Signed Up:||3/17/2012|
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|Highest Comment Rank:||#46|
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|Total Comments Made:||10384|
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#84 - anon (07/05/2016) [-]
Honestly all you really need is for your internal organs and bones n shit to withstand the rapid acceleration from fall speed to stopped and you wouldn't even need leg strength, just do a belly flop.
#70 - skrynox (07/05/2016) [-]
The logic is sound, but the problem is the difference in forces.
If you fall down an elevator shaft in an elevator, you could be going about 50mph+, so if you jump off the elevator floor with a force of 3mph upwards, you'll then be falling 47mph.
It doesn't work, you basically just die a little less.
#58 - haroldsaxon (07/05/2016) [-]
That's not how that works. While you might make your platform drop quicker, you would simultaneously push yourself in the opposite direction. If the platform was falling with a speed of 5, you would need a force much greater than 5 if you want to hit 0, but you can hit zero.
#65 - Haentar (07/05/2016) [-]
I'm gonna tackle this like conservation of energy, done simply
Gravitational Potential Energy is mass * gravitational accel. * height .
m=whatever mass it is, g = 9.8 m/s^2, height=2 or 3 met.
Kinetic Energy is 1/2 * mass * velocity^2 .
Fuck I don't feel like converting ft to meeters, maybe let's compare 2m vs 3m instead.
In the beginning, it's all PE, at the end, it's all KE.
So PE(at the top) = KE at the bottom.
v=(2*g*h)^(1/2) [spoiler] The bottom velocity is equal to the square root of 2 times the grav. acce. times the height.
falling from 3 meters would yield ~~ 7.7 meters/second at the bottom.
falling from 2 meters would yield ~~ 6.3 meters/second at the bottom. [/spoiler]
So, if you wanted to jump at the bottom of a 3 meter drop (around 9 feet-ish) to make it like a 2 meter drop (around 6 feet-ish, you're guessing it won't break your legs), you'd need to be able to jump up at a speed of 1.4 meters/second right before you hit the ground, something like 3.13 miles per hour. Idk how possible this would be.
but my advice is the following
(Also, learning how to roll properly (ie parkour rolls) when you hit the ground would be much better unless you're falling really far or onto a bad surface for rolls).
#68 - Haentar (07/05/2016) [-]
Oh hey, according to >>#53, the maximum recorded jump height was round 60 inches, or like 1.5 meters. Let's just do that conservation thing the other way round then.
(1/2)*m*v^2=m*g*h because it's still v at the bottom, h at the top.
v=the square root of (2*9.8*1.5)
v to jump that high would therefore be around 5.4 meters per second
and we need to jump up at 1.4 meters/second in order to make a 3 meter drop as fast as a 2 meter drop.
Seems doable. Huh.
Just don't lose your balance when you jump I guess.
Also idk what you'd be jumping off of at that low of a speed.
#53 - ninjaroo (07/05/2016) [-]
Assuming you succeed at jumping Which is a big assumption. It's harder to jump when you're falling, and the thing you're falling with has to be heavy enough that you don't just push it away , the maximum recorded jump was 60 inches, by a basketball player. So HE could do it, the average human could take off maybe a third of the distance.
#86 - anon (07/05/2016) [-]
Who is your profile pic?
#89 - anon (07/06/2016) [-]
#64 - raunchyftw (07/05/2016) [-]
#67 - anon (07/05/2016) [-]
the example used was an elevator not a metal pallet.
#35 - dtox (07/05/2016) [-]
your legs would be fighting against the force that is the weight of your body dropping from 10 feet. If you were strong enough, it might work, but you'd have to be pretty damn strong...like every day is leg day strong.
If I knew the exact math behind it I could probably tell you, but I don't.
#45 - anon (07/05/2016) [-]
Uh, here is my humble scienceanon explanation if u wanna read If you did nothing and just accepted your fate then the elevator would exert Ffall=m*dv/dt (F=m*a where a = change in velocity over time falling) force on your legs.
If you jumped and got airborne a bit before hitting the ground the elevator would exert two forces on you.
The equal n opposite force from you jumping, Fjump=m*a2(where a2 is whatever you jump at, around 17m/s if you have a 4 foot vertical)
Then the force from you hitting the elevator
Felevator=Ffall(m*dv/dt)-Fjump(m*a2) (the force of falling minus what you took away by jumping)
As you can see when you finally hit the bottom after jumping the elevator exerts less force on your legs and this is the result that matters in this case.
HOWEVER, it's important to remember that the total force exerted on your legs is the same if you jump or not, jumping early enough to get into the air but not hit the elevator roof just splits it up into two lesser forces, but because our legs re-extend after being compressed we can assume the forces don't add together to damage our legs as long as you actually get into the air for a bit.
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