Doominabox
Level 20 Comments: Peasant
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Send mail to Doominabox Block Doominabox Invite Doominabox to be your friend Last status update:  

 
Date Signed Up:  10/08/2010 
Last Login:  2/01/2013 
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latest user's comments
#789  just to watch him die?  01/02/2013 on What's one secret that...  0 
#27  /watch?v=1IKbtBbl3EA  11/19/2012 on too soon?  0 
#595  Obviously a lie, god  11/19/2012 on 10%  0 
#166  obviously im not going to accept your theory, and you mine, so…  11/18/2012 on TODAY  0 
#164  the eqation wrote should have said either 9=10x.9.. … [+] (2 new replies)  11/18/2012 on TODAY  0 
#165 
GeorgeBush (11/18/2012) [] That still doesn't mean that in the end .999... doesn't = 1, because it does. I can't explain it as well as my teacher could, but it's basic mathematic theory that they, and all other infinitely repeating integers with .999... equals the same number rounded up. 46.999... = 47, etc #166 
Doominabox (11/18/2012) [] obviously im not going to accept your theory, and you mine, so lets both just stop talking  
#161  what you're not getting is that x≠.99999.... because she cha… [+] (4 new replies)  11/18/2012 on TODAY  0 
#163 
GeorgeBush (11/18/2012) [] She didn't change what x equaled, she changed the equation x was used in. In math you always do to one side of the equation what you do to the other, as I'm sure you know. She simply multiplied the starting equation by 10 on each side. (1) x = .999... multiplied by 10 is 10x = 9.999... , the value of x did not change. If you then divide the equation 10x = 9.999... (in which you claim x no longer equals .999...) by 10 you get (1) x = .999... again, meaning that in the two equations x remains constant. #164 
Doominabox (11/18/2012) [] the eqation wrote should have said either 9=10x.9.. or 9x=9x just because it was writen like that, doesn't mean its true X=5 50X=50 (times it by 10) 49X=49 (i subtracted one from each side) X=1 (divided by 49) and presto 5=1 #165 
GeorgeBush (11/18/2012) [] That still doesn't mean that in the end .999... doesn't = 1, because it does. I can't explain it as well as my teacher could, but it's basic mathematic theory that they, and all other infinitely repeating integers with .999... equals the same number rounded up. 46.999... = 47, etc #166 
Doominabox (11/18/2012) [] obviously im not going to accept your theory, and you mine, so lets both just stop talking  
#159  https://www. [url deleted] ?feature=player_embedded &v…  11/18/2012 on TODAY  0 
#158  Comment deleted  11/18/2012 on TODAY  0 
#157  exactly thats what she did wrong [+] (6 new replies)  11/18/2012 on TODAY  0 
#160 
GeorgeBush (11/18/2012) [] No, she did nothing wrong. Every step of the equation had the same process done unto both sides. Subtracting x and subtracting .999... is the same processes, using the same amount, meaning that it is a perfectly valid. They said x = .999... meaning subtracting .999.... and subtracting x makes no difference as they are the same number. The reason they subtracted x on one side and .999... on one side is because one side (left) already had x as a variable, and the right side did not. #161 
Doominabox (11/18/2012) [] what you're not getting is that x≠.99999.... because she changed it after the first step you would not subtract x from the other side the actual equation would be 9=10x.99999.... wich is not the same as 9=9x #163 
GeorgeBush (11/18/2012) [] She didn't change what x equaled, she changed the equation x was used in. In math you always do to one side of the equation what you do to the other, as I'm sure you know. She simply multiplied the starting equation by 10 on each side. (1) x = .999... multiplied by 10 is 10x = 9.999... , the value of x did not change. If you then divide the equation 10x = 9.999... (in which you claim x no longer equals .999...) by 10 you get (1) x = .999... again, meaning that in the two equations x remains constant. #164 
Doominabox (11/18/2012) [] the eqation wrote should have said either 9=10x.9.. or 9x=9x just because it was writen like that, doesn't mean its true X=5 50X=50 (times it by 10) 49X=49 (i subtracted one from each side) X=1 (divided by 49) and presto 5=1 #165 
GeorgeBush (11/18/2012) [] That still doesn't mean that in the end .999... doesn't = 1, because it does. I can't explain it as well as my teacher could, but it's basic mathematic theory that they, and all other infinitely repeating integers with .999... equals the same number rounded up. 46.999... = 47, etc #166 
Doominabox (11/18/2012) [] obviously im not going to accept your theory, and you mine, so lets both just stop talking  
#156  also, you have to do exactly the same on both sides, so when t…  11/18/2012 on TODAY  0 