Doominabox
Level 20 Comments: Peasant
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In math you always do to one side of the equation what you do to the other, as I'm sure you know. She simply multiplied the starting equation by 10 on each side.
(1) x = .999... multiplied by 10 is
10x = 9.999... , the value of x did not change.
If you then divide the equation 10x = 9.999... (in which you claim x no longer equals .999...) by 10 you get
(1) x = .999... again, meaning that in the two equations x remains constant.
9=10x.9..
or 9x=9x
just because it was writen like that, doesn't mean its true
X=5
50X=50 (times it by 10)
49X=49 (i subtracted one from each side)
X=1 (divided by 49)
and presto 5=1
you would not subtract x from the other side the actual equation would be
9=10x.99999....
wich is not the same as
9=9x
In math you always do to one side of the equation what you do to the other, as I'm sure you know. She simply multiplied the starting equation by 10 on each side.
(1) x = .999... multiplied by 10 is
10x = 9.999... , the value of x did not change.
If you then divide the equation 10x = 9.999... (in which you claim x no longer equals .999...) by 10 you get
(1) x = .999... again, meaning that in the two equations x remains constant.
9=10x.9..
or 9x=9x
just because it was writen like that, doesn't mean its true
X=5
50X=50 (times it by 10)
49X=49 (i subtracted one from each side)
X=1 (divided by 49)
and presto 5=1