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237
Apply early and know Hun . compassion
t. drive Yerkes
I whe. 11 can i apply
what does 2 k' tll 'tnmt
i actually dam _ haw to . r mat
t. drive Yerkes
I whe. 11 can i apply
what does 2 k' tll 'tnmt
i actually dam _ haw to . r mat
...
 
What do you think? Give us your opinion. Anonymous comments allowed.
#2

anonymous (05/05/2013) [+] (4 replies)
He could be in the process of writing the .5 at the end?
#15

nyanko (05/05/2013) [+] (1 reply)
Look closely, it reads 37 ≠ 2 * 18
(it uses the does not equal symbol).
He's probably trying to disprove something.
(it uses the does not equal symbol).
He's probably trying to disprove something.
#22

schwerdaddy (05/05/2013) [+] (6 replies)
He is showing how the base 10 numeric system works:
(2 x 10^2) + (3 x 10^1) + (7 x 10^0) =
200 + 30 + 7 =
237
(2 x 10^2) + (3 x 10^1) + (7 x 10^0) =
200 + 30 + 7 =
237
#19

daedrakiller (05/05/2013) []
2x18=37
x=1.027777777777778
2x=2.055555555555556
2.055555555555556*18=37
x=1.027777777777778
2x=2.055555555555556
2.055555555555556*18=37
#42

bensho (05/05/2013) [+] (1 reply)
237 is the code for electronic device in use at my place of learning.
#82

wisdombranch (05/05/2013) [+] (1 reply)
This is a perfectly legitimate equation in base 9.
>>>>>Base 9: 37 = 2 x 18 > (3*9 + 7) = (2) x (1*9 + 8)
>>>>>Base 10 equivalent: 34 = 2 x 17 > (3*10 + 4) = (2) x (1*10 + 7)
Assuming the "237" is already in base nine (and he is not referring to two hundred thirtyseven), then here is the solution:
237[9] = (2*(9^2)) + (3*9) + (7) =
(2*81) + (3*9) + 7 =
162 + 27 + 7 = 196[10]
237[9] = 196[10]
>>>>>Base 9: 37 = 2 x 18 > (3*9 + 7) = (2) x (1*9 + 8)
>>>>>Base 10 equivalent: 34 = 2 x 17 > (3*10 + 4) = (2) x (1*10 + 7)
Assuming the "237" is already in base nine (and he is not referring to two hundred thirtyseven), then here is the solution:
237[9] = (2*(9^2)) + (3*9) + (7) =
(2*81) + (3*9) + 7 =
162 + 27 + 7 = 196[10]
237[9] = 196[10]
#20

dafuckisthisshit (05/05/2013) [+] (1 reply)
keep the fucking vague ass english questions out of math class!