I have a hairless guinea pig, he's super cute and his name is wilber. The only thing is his balls are freaking huge and there's no hair to cover them! It's kinda gross but otherwise he's cute.
The limit and the actuality are two totally different things.
Also, approaches zero, NEVER equals zero.
Go to college majoring in mathematics before you start talking crap.
You're not taking into account the fact that the barber must remove entire hairs from the guinea pig's body, not fractions.
Eventually a single hair will be left, and in accordance with the conventions for rounding numbers it will be removed entirely, leaving the rodent entirely nonhirsute.
Technically though, you could calculate where it ends. You could integrate under the graph of hair removed to times cut and find the total hair removed, then count the total amount of hair on the guinea pig and know when it all gets removed
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necroshiz**User deleted account** has deleted their comment []
You are thinking in a more physical world which this deals in, .0000000000000000000000000000000000000000000... so insignificant that you could get to a point where it is zero. Even physically you might reach a planck length which is the smallest possible length physically obtainable.
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necroshiz**User deleted account** has deleted their comment []
I dont think integration means what you think it means...., You'll have to take the limit of 1/(n^2) as n > infinity. and yes it does get to zero, plz take Cal II before you start throwing out words you dont even understand. Oh. p.s. You can also use the Nth term, and pseries test on this.
I think you need to take higher than calc 2, if an integral has a limit of infinity, we can use
x=infinity
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a
which will let you integrate with a limitless graph. Not only can you integrate things with limits of infinity, but using improper integration you can integrate the area under an asymptote, for example the area under the graph 1/(x^0.5)
1
integral 1/(x^0.5)dx calculates out to equal 2
0
So yes, I do know what integral means, and i've taken calc 2 and further, this is degree level maths, look it up if you like
"x=infinity
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a "
When you're integrating a function, you get another function for which you're evaluating the limit as x>infinity (in this case,[F(X)F(a)]).So basically that's the limit and not the actual value it touches. It's like saying that ln[0]=infinity.But technically the ln is not defined in the point x=0,so you can't compute ln[0].
if F(x)= int 1/(x^2) dx = x^1 + c, this is your indefinite integral
using
x=infinity
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a
(the limit formula)
we find F(X) is 0,
and F(a) is 1,
Hence, your solved integral (area under graph) is 0(1) or 1, so a graph with no end has a finite value of the area under it, in a similar way that the power series of sin(x) converges to a set value, as does the area under an indefinite integral
If you do maths at university (or college I think if you're American, or education for age 18+ in whatever country you're in) you should find out about stuff like this
A lot of people are saying that it will take forever. This is incorrect.
Some mention indefinite integrals. This is too difficult.
<<< It in fact only requires a summation and a limit.
Since this is the sum of everything from half a haircut on down (as described), it will take just as long as a regular haircut.
This is known as Zeno's Paradox, and has been expressed in several different ways, but it all boils down to these equations.
* Note that this doesn't include time like waiting in line, or the guinea pig looking in the mirror or other things. Mathematicians are douchebags like that. Same with physicists. It would also cost an infinite amount...
you are saying that it will be as long as regular haircut because you excluded most of times, such as waiting in line and some stuffs and you claimed that it would cost an infinite amount, so if you included these times, it should take forever since guinea pig has to walk outside and some stuffs infinite time.
Under Zeno's paradox, if he keeps getting half his hair cut, he will never get it all removed. He'll get infinitely close, but never completely.
You're never actually reaching 1 with your limit there, but rather converging towards 1. The limit of the sums is 1, but the sum never actually is.
Since you're never cutting off all of what's left, but only half, you'll never reach 100% removal, because, in layman's terms, zero is not half of a nonzero quantity.
"I'm now shaving this young mans head, adding hair, this young mans who's troubles are with gangs, money, sex and violence. This young man who demanded a fro instead of a buzz cut. This young man who just ran over 2 people and shot a hooker with a military shotgun... I.. am Morgan Freeman, the barber, the story teller"
Well yeah even if it never really reaches a complete haircut there's gonna be like 1/999999999th of a cm. of hair so i mean you can just pull it out or ignore it or something unless this hamster has like OCD
Well an infinite amount of cuts implies an infinite amount of time which our Guinea Pig* here probably wants to avoid, hence "This is going to take FOREVER."
Maybe you comment level was reset?I saw you commented a picture in march.Also i'm pretty sure recently the level required for posting pics was increased