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> hey anon, wanna give your opinion?
asd
#76 to #2

ravenalexis
Reply +2 123456789123345869
(04/30/2013) [] I have a hairless guinea pig, he's super cute and his name is wilber. The only thing is his balls are freaking huge and there's no hair to cover them! It's kinda gross but otherwise he's cute.
#7 to #2

trojandetected
Reply +6 123456789123345869
(04/29/2013) [] **trojandetected rolled a random image posted in comment #1790136 at Friendly **
hippos look like shaved guinea pigs
hippos look like shaved guinea pigs
#31

marcalo
Reply +195 123456789123345869
(04/29/2013) [] Mathematically speaking it can never be done completely.
#156 to #31

lieutenantshitface **User deleted account**
3 123456789123345869
has deleted their comment [] #86 to #31

gjsmothefirst
Reply 2 123456789123345869
(04/30/2013) [] It can be, see www.funnyjunk.com/funny_pictures/4563591/Haircut+deal/85#85
#114 to #31

vampireinarm
Reply 1 123456789123345869
(04/30/2013) [] he did say it was going to take forever
#107 to #31

bummerdrummer
Reply +1 123456789123345869
(04/30/2013) [] "this is going to take forever"
thatsthejoke.jpg
thatsthejoke.jpg
#52 to #31

Spavaloo
Reply +24 123456789123345869
(04/30/2013) [] You're not taking into account the fact that the barber must remove entire hairs from the guinea pig's body, not fractions.
Eventually a single hair will be left, and in accordance with the conventions for rounding numbers it will be removed entirely, leaving the rodent entirely nonhirsute.
Eventually a single hair will be left, and in accordance with the conventions for rounding numbers it will be removed entirely, leaving the rodent entirely nonhirsute.
#82 to #52

anon id: 80c4d4ff
Reply 0 123456789123345869
(04/30/2013) [] But what happens if the begins cutting the last hair by half and the by it's half and so on
By the time he reached the length of a single atom of hair, the other hairs from the pig's body should have grown at least 1 atom tall
By the time he reached the length of a single atom of hair, the other hairs from the pig's body should have grown at least 1 atom tall
#108 to #82

jakeattack
Reply +7 123456789123345869
(04/30/2013) [] then he splits the ******* atoms and boom
#3

anon id: 8454dda3
Reply 0 123456789123345869
(04/29/2013) [] It's going to take forever but in the end it will do the job.
#61 to #3

meltingrain
Reply 0 123456789123345869
(04/30/2013) [] No it won't .... its an infinite sequence
#4 to #3

fluttershyismine
Reply +48 123456789123345869
(04/29/2013) [] mathematically speaking dat **** convergeres to 0
#21 to #9

baconfattie
Reply 0 123456789123345869
(04/29/2013) [] I was looking for thiiiiiiiiiiiiiiiiiiiis in my pc
#13 to #6

eddymolly
Reply +1 123456789123345869
(04/29/2013) [] Technically though, you could calculate where it ends. You could integrate under the graph of hair removed to times cut and find the total hair removed, then count the total amount of hair on the guinea pig and know when it all gets removed
#64 to #55

mcrut
Reply 0 123456789123345869
(04/30/2013) [] You are thinking in a more physical world which this deals in, .0000000000000000000000000000000000000000000... so insignificant that you could get to a point where it is zero. Even physically you might reach a planck length which is the smallest possible length physically obtainable.
#39 to #16

giguelingueling
Reply 0 123456789123345869
(04/30/2013) [] yes become hairs are quanta, or at the very least the matter of the hairs are quanta. At some point you won't be able to split the thing in half.
#116 to #39

giguelingueling
Reply 0 123456789123345869
(04/30/2013) [] wtf, I was ******* drunk. This **** make no sense
#49 to #13

anon id: ca553390
Reply 0 123456789123345869
(04/30/2013) [] I dont think integration means what you think it means...., You'll have to take the limit of 1/(n^2) as n > infinity. and yes it does get to zero, plz take Cal II before you start throwing out words you dont even understand. Oh. p.s. You can also use the Nth term, and pseries test on this.
[url deleted]
[url deleted]
#136 to #49

eddymolly
Reply 0 123456789123345869
(04/30/2013) [] I think you need to take higher than calc 2, if an integral has a limit of infinity, we can use
x=infinity
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a
which will let you integrate with a limitless graph. Not only can you integrate things with limits of infinity, but using improper integration you can integrate the area under an asymptote, for example the area under the graph 1/(x^0.5)
1
integral 1/(x^0.5)dx calculates out to equal 2
0
So yes, I do know what integral means, and i've taken calc 2 and further, this is degree level maths, look it up if you like
x=infinity
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a
which will let you integrate with a limitless graph. Not only can you integrate things with limits of infinity, but using improper integration you can integrate the area under an asymptote, for example the area under the graph 1/(x^0.5)
1
integral 1/(x^0.5)dx calculates out to equal 2
0
So yes, I do know what integral means, and i've taken calc 2 and further, this is degree level maths, look it up if you like
#150 to #136

fluttershyismine
Reply 0 123456789123345869
(04/30/2013) [] "x=infinity
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a "
When you're integrating a function, you get another function for which you're evaluating the limit as x>infinity (in this case,[F(X)F(a)]).So basically that's the limit and not the actual value it touches. It's like saying that ln[0]=infinity.But technically the ln is not defined in the point x=0,so you can't compute ln[0].
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a "
When you're integrating a function, you get another function for which you're evaluating the limit as x>infinity (in this case,[F(X)F(a)]).So basically that's the limit and not the actual value it touches. It's like saying that ln[0]=infinity.But technically the ln is not defined in the point x=0,so you can't compute ln[0].
#151 to #150

eddymolly
Reply 0 123456789123345869
(04/30/2013) [] i'll give you an example
"x=infinity
integral 1/(x^2) dx
x=a
if F(x)= int 1/(x^2) dx = x^1 + c, this is your indefinite integral
using
x=infinity
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a
(the limit formula)
we find F(X) is 0,
and F(a) is 1,
Hence, your solved integral (area under graph) is 0(1) or 1, so a graph with no end has a finite value of the area under it, in a similar way that the power series of sin(x) converges to a set value, as does the area under an indefinite integral
If you do maths at university (or college I think if you're American, or education for age 18+ in whatever country you're in) you should find out about stuff like this
"x=infinity
integral 1/(x^2) dx
x=a
if F(x)= int 1/(x^2) dx = x^1 + c, this is your indefinite integral
using
x=infinity
integral f(x) dx = lim(X> infinity) [F(X)F(a)]
x=a
(the limit formula)
we find F(X) is 0,
and F(a) is 1,
Hence, your solved integral (area under graph) is 0(1) or 1, so a graph with no end has a finite value of the area under it, in a similar way that the power series of sin(x) converges to a set value, as does the area under an indefinite integral
If you do maths at university (or college I think if you're American, or education for age 18+ in whatever country you're in) you should find out about stuff like this
#57

rifee
Reply +15 123456789123345869
(04/30/2013) [] I was gonna get a haircut today, but then I decided not to.
#134 to #57

emanalvarez
Reply +1 123456789123345869
(04/30/2013) [] i was gonna get a haircut, but then i got high.
#85

gjsmothefirst
Reply +15 123456789123345869
(04/30/2013) [] A lot of people are saying that it will take forever. This is incorrect.
Some mention indefinite integrals. This is too difficult.
<<< It in fact only requires a summation and a limit.
Since this is the sum of everything from half a haircut on down (as described), it will take just as long as a regular haircut.
This is known as Zeno's Paradox, and has been expressed in several different ways, but it all boils down to these equations.
* Note that this doesn't include time like waiting in line, or the guinea pig looking in the mirror or other things. Mathematicians are douchebags like that. Same with physicists. It would also cost an infinite amount...
Some mention indefinite integrals. This is too difficult.
<<< It in fact only requires a summation and a limit.
Since this is the sum of everything from half a haircut on down (as described), it will take just as long as a regular haircut.
This is known as Zeno's Paradox, and has been expressed in several different ways, but it all boils down to these equations.
* Note that this doesn't include time like waiting in line, or the guinea pig looking in the mirror or other things. Mathematicians are douchebags like that. Same with physicists. It would also cost an infinite amount...
#100 to #85

anon id: 37b556c8
Reply 0 123456789123345869
(04/30/2013) [] you are saying that it will be as long as regular haircut because you excluded most of times, such as waiting in line and some stuffs and you claimed that it would cost an infinite amount, so if you included these times, it should take forever since guinea pig has to walk outside and some stuffs infinite time.
i don't see your point...
i don't see your point...
#154 to #100

therealtjthemedic
Reply 1 123456789123345869
(04/30/2013) [] what are you even trying to say
#115 to #85

markertemp
Reply +6 123456789123345869
(04/30/2013) [] Under Zeno's paradox, if he keeps getting half his hair cut, he will never get it all removed. He'll get infinitely close, but never completely.
You're never actually reaching 1 with your limit there, but rather converging towards 1. The limit of the sums is 1, but the sum never actually is.
Since you're never cutting off all of what's left, but only half, you'll never reach 100% removal, because, in layman's terms, zero is not half of a nonzero quantity.
You're never actually reaching 1 with your limit there, but rather converging towards 1. The limit of the sums is 1, but the sum never actually is.
Since you're never cutting off all of what's left, but only half, you'll never reach 100% removal, because, in layman's terms, zero is not half of a nonzero quantity.
#27

cosmohill
Reply +29 123456789123345869
(04/29/2013) [] Is anyone else confused by the completely impossible reflection in the second to last panel?
#131 to #129

bitchplzzz
Reply +5 123456789123345869
(04/30/2013) [] "I'm now shaving this young mans head, adding hair, this young mans who's troubles are with gangs, money, sex and violence. This young man who demanded a fro instead of a buzz cut. This young man who just ran over 2 people and shot a hooker with a military shotgun... I.. am Morgan Freeman, the barber, the story teller"