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#425 to #75

psykobear (03/16/2013) []
x^2 + 4x  21 = 0 (Universe = Natural Numbers)
Quadratic Formula: (b +/ (b^2  4ac)^(1/2)) / 2a
x = (4 +/ (4^2  4(1)(21))^(1/2)) / 2(1)
x = (4 +/ (16  (84))^(1/2)) / 2
x = (4 +/ 100^(1/2)) / 2
x = (4 +/ 10) / 2
x = 6/2 or 6/2
x = 3 or 3
Only Natural Numbers, so:
x = 3
Half Life 3 confirmed
Quadratic Formula: (b +/ (b^2  4ac)^(1/2)) / 2a
x = (4 +/ (4^2  4(1)(21))^(1/2)) / 2(1)
x = (4 +/ (16  (84))^(1/2)) / 2
x = (4 +/ 100^(1/2)) / 2
x = (4 +/ 10) / 2
x = 6/2 or 6/2
x = 3 or 3
Only Natural Numbers, so:
x = 3
Half Life 3 confirmed