Untitled. It's SCIENCE.. Oh look, something that involves basic physics...Everyone pull out your PhD and act like you are intelligent. science
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> hey anon, wanna give your opinion?
asd
#36 - bostpost
Reply +44 123456789123345869
(02/17/2013) [-]
Oh look, something that involves basic physics...Everyone pull out your PhD and act like you are intelligent.


Oh look, something that involves basic physics...Everyone pull out your PhD and act like you are intelligent.
#41 to #36 - thedarkestrogue
Reply 0 123456789123345869
(02/18/2013) [-]
Yup. In a ******* nutshell.   
MFW reading the comments.
Yup. In a ******* nutshell.
MFW reading the comments.
User avatar #51 to #36 - OldSnake
Reply 0 123456789123345869
(02/18/2013) [-]
Phyyyyyyyysics. PHYSICS! Physicphysicphysicphysicphysicphysics Physics!
User avatar #4 - shinycharizard
Reply +10 123456789123345869
(02/17/2013) [-]
What the equation, or sentence rather, is saying; It's not the fall that kills you, it's the impact.

God damn I love physics.
#23 to #4 - bigmanblue
Reply +1 123456789123345869
(02/17/2013) [-]
strictly speaking its saying its not the speed that kills you its the force but in laymans terms i supose you would be right
User avatar #30 to #23 - clingy
Reply +2 123456789123345869
(02/17/2013) [-]
it's the force, which is the change in momentum (time derivatve) so if you have a large change in momentum over a small period of time, i.e. crashing into the ground, thats what kills you.
#32 to #30 - clingy
Reply +4 123456789123345869
(02/17/2013) [-]
like here
User avatar #37 to #30 - shinycharizard
Reply +1 123456789123345869
(02/17/2013) [-]
Reminds me of the time when Spiderman killed Gwen Stacy because his web wasn't elastic enough, so the sharp change of momentum exerted a huge force on her, snapping her neck.

And Spidey had to go and blame it on Green Goblin.
#16 to #4 - clingy
Reply +3 123456789123345869
(02/17/2013) [-]
ask a physics major anything
ask a physics major anything
User avatar #24 to #16 - shinycharizard
Reply +3 123456789123345869
(02/17/2013) [-]
How many swags do you have?
User avatar #29 to #24 - clingy
Reply +5 123456789123345869
(02/17/2013) [-]
5 kilograms
User avatar #18 to #16 - derkarus
Reply +1 123456789123345869
(02/17/2013) [-]
Wanna do my homework for me?
User avatar #19 to #18 - clingy
Reply +2 123456789123345869
(02/17/2013) [-]
Haha maybe i can help :)
User avatar #20 to #19 - derkarus
Reply +1 123456789123345869
(02/17/2013) [-]
A Ferrari Maranello passes a ford Pinto on the 401. The Maranello is constantly accelerating at aM. The Pinto driver accelerates at a P the instant she sees the Ferrari Pass by. At the instant the two cars pass by each other, their speeds are vM, and vP, and vM>vP. At what time t=f(vm, vp, am, ap) will the pinto catch the maranello?
User avatar #21 to #20 - clingy
Reply +1 123456789123345869
(02/17/2013) [-]
so at first the marnello is behind the pinto, then the pinto accelerates and passes the marnello?
User avatar #22 to #21 - derkarus
Reply +1 123456789123345869
(02/17/2013) [-]
yep, have to find out when that happens.
User avatar #26 to #22 - clingy
Reply +2 123456789123345869
(02/17/2013) [-]
ok here's what i have:
since they will have travelled the same distance (x) from the time the maranello passed the pinto to when the time the pinto catches up, you can set the two equal to each other. The maranello's distance is x=(vm)t+((am)t^2)/2
The pinto's distance is x=(vp)t+((ap)t^2)/2
Set the two x's equal to each other and solve for t
I got t=2(vm-vp)/(ap-am)
User avatar #27 to #26 - derkarus
Reply +1 123456789123345869
(02/17/2013) [-]
Ah, thought it was something along those lines but I am always just off on one aspect of it that ***** everything up. Thanks!
User avatar #28 to #27 - clingy
Reply +1 123456789123345869
(02/17/2013) [-]
i hope that's right haha i haven't done kinematics like this in years :) and you're welcome
User avatar #25 to #22 - derkarus
Reply 0 123456789123345869
(02/17/2013) [-]
I've gathered that the pintos acceleration is larger than the Maranello, and have made a graph(v/t) with vm starting over vp and the lines crossing about half way
#34 - excludedbug
Reply +8 123456789123345869
(02/17/2013) [-]
It´s not the fart that kills you, it´s the smell.
User avatar #45 to #34 - runeception
Reply 0 123456789123345869
(02/18/2013) [-]
Yes, JUST YES!
#56 to #34 - ogomer
Reply 0 123456789123345869
(02/18/2013) [-]
#35 - herrstig **User deleted account**
Reply +4 123456789123345869
(02/17/2013) [-]
#50 - tripflys **User deleted account**
+1 123456789123345869
has deleted their comment [-]
#59 to #50 - fedegon
Reply 0 123456789123345869
(02/18/2013) [-]
NO! I've just gotten over it! Why did you bring it back?
#60 to #59 - tripflys **User deleted account**
+1 123456789123345869
has deleted their comment [-]
#61 to #60 - fedegon
Reply 0 123456789123345869
(02/18/2013) [-]
You may be sorry, but you're not forgiven.
#42 - thedarkestrogue
Reply +1 123456789123345869
(02/18/2013) [-]
MFW everyone in the comments think they're physicists.
MFW everyone in the comments think they're physicists.
#43 to #42 - arandomanon
Reply +1 123456789123345869
(02/18/2013) [-]
Understanding the post makes me a physicist?
User avatar #53 to #43 - HarvietheDinkle
Reply +1 123456789123345869
(02/18/2013) [-]
No, it's the people trying to show off basic physics knowledge.
User avatar #55 to #53 - thedarkestrogue
Reply 0 123456789123345869
(02/18/2013) [-]
^this.
User avatar #40 - Jackimole
Reply +1 123456789123345869
(02/17/2013) [-]
This is dumb.
"Look at me, I know what a kinematic equation is!"

What's the point?
User avatar #38 - lordbyronxiv
Reply +1 123456789123345869
(02/17/2013) [-]
F = dP/dt says it better.
#15 - xhopesandfearsx
Reply 0 123456789123345869
(02/17/2013) [-]
First thing that comes to mind.
First thing that comes to mind.
#17 to #15 - anon id: c8a53815
Reply 0 123456789123345869
(02/17/2013) [-]
why would you do that
User avatar #57 to #15 - ArcaciaStrain
Reply 0 123456789123345869
(02/18/2013) [-]
What's this from?
#64 to #57 - xhopesandfearsx
Reply +1 123456789123345869
(02/18/2013) [-]
The BBC series Sherlock
#12 - unhappyface
Reply +1 123456789123345869
(02/17/2013) [-]