How to Math. . 90% of math graduates can' t solve this equation. this equation cannot be true and cant be solved fc
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What do you think? Give us your opinion. Anonymous comments allowed.
User avatar #26 - amegaara (01/04/2013) [+] (8 replies)
this equation cannot be true and cant be solved
#1 - quietbrony (01/04/2013) [+] (20 replies)
Accidently learning math on internet
Accidently learning math on internet
#88 - flyslasher (01/04/2013) [+] (8 replies)
y + 2 = y
2 = y - y
2 = 0
( 2 != 0 )
No Solution
#28 - simeonc (01/04/2013) [+] (10 replies)
Y = Y + 2
Programmers thinking:-
2, 4, 6, 8 etc

User avatar #62 - thelordofrepost (01/04/2013) [+] (3 replies)
Y is a letter. It cannot be added to a number.
User avatar #195 - thewalruss (01/05/2013) [+] (1 reply)
actually, Y = ∞...

∞ + 2 = ∞

By the way, that is not a infinity simbol... those are boobs.
#193 - jamesrustler (01/05/2013) [+] (1 reply)
I read in the comments that it can't be solved because it's a meaningless equation.    
God damn I wish I was smart enough to understand 			****		 like this.
I read in the comments that it can't be solved because it's a meaningless equation.

God damn I wish I was smart enough to understand **** like this.
#174 - predalien (01/05/2013) [-]
**predalien rolled a random image posted in comment #17 at Racist Barn Racist Barn 1 2 3 4 ** mfw
User avatar #40 - therianek (01/04/2013) [+] (5 replies)
Imo i would use derivation on this...
first derivation:
f(x) : y+2 = y
f(x)' : 1 = 1
because derivation from y is 1 and derivation from 2 is 0

Problem solved
#47 to #40 - quarklion (01/04/2013) [-]
Except that didn't really solve it, since you didn't even adress the equation itself.
You didn't even try to adress it as an equation. Equations are solved by finding the values of the variable(commonly x, but here it's y) for which both sides are equal.
Functions on the other hand is finding the output for different values of x.
An example of an equation is 2+x=2x with the solution being x=2. Equations can exist for which there is multiple solutions. An example is 1=x^2 with both x=1 and -1 being valid answers
An example of a function is f(x)=3x+7 with there being a different output for each value of x. Functions can exist where certain values of x is invalid. An example is f(x)=1/x with x=0 being invalid.
As a sidenote f(x) means function of x, so for your invalid attempt you should've written f(y).

Also my "attempt" at solving this.
No valid answer.
User avatar #89 - ithinkimfunny (01/04/2013) [-]
This equation is per definition ******** .
#79 - cheezitman (01/04/2013) [+] (8 replies)
I guess I'm going to have to solve it sometime...

1y+2=1y (the reason I put 1y instead of y is because it is easier to solve)
Subtract 1y from both sides
Divide by 0 on both sides
since you can't divide by zero it isn't possible
so y=Undefined
User avatar #180 - Kabutops (01/05/2013) [-]
uhm...there's no answer for the variable? (90% of gradautes my ass)
User avatar #59 - traveltech (01/04/2013) [-]
y is simply not a real number
User avatar #223 - supermegasherman (01/05/2013) [-]
no solution
#210 - skinless (01/05/2013) [-]
this thread....i just don't know
this thread....i just don't know
#130 - pedobearson (01/04/2013) [-]
That's because this is impossible.
User avatar #83 - moyete (01/04/2013) [-]
Math is kill.
#19 - ipmules (01/04/2013) [+] (3 replies)
Here we go. This goes for any of the commonly known sets of numbers in mathematics, namely the naturals, integers, rationals, reals and complex. For any element in the set (we'll call it x, and in this example we'll just deal with naturals,) there exists a unique solution to the equation x+a=x=a+x, meaning a is the identity element in respect to addition, or is the additive identity. In all of these sets, the additive identity is 0. That means that x+a=x=a+x is only true when a=0. Since this is a case where a=2, it can no longer hold true for any x in any of the above sets.

TL:DR: There exists no solution.
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