The Dark Equation. Found this trolling the interwebz . Batman Equador. This graph has no parent............functions dark equation batman Awesome robo
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The Dark Equation

Found this trolling the interwebz

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Batman Equador
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User avatar #7 - piscochugger (02/27/2012) [+] (2 replies)
This graph has no parent............functions
#1 - crawdady (02/27/2012) [+] (1 reply)
User avatar #15 - partywagon (02/28/2012) [+] (3 replies)
funnyjunk.com/funny_picture... posted this months ago, 16 thumbs :(
#10 - TobyMD (02/28/2012) [+] (2 replies)
Because he's the graph our class deserves, but not the one it needs right now...
User avatar #27 - xcmxcmx (02/28/2012) [+] (3 replies)
this could be complete ******** and nobody would ever know.
User avatar #18 - whydidyoudothat (02/28/2012) [-]
the virginity is strong in this one
#37 - obliquezombie (02/28/2012) [+] (6 replies)
"I found this trolling the interwebz."   
   
Trolling. You keep saying this word, and I do not think you know what it means.
"I found this trolling the interwebz."

Trolling. You keep saying this word, and I do not think you know what it means.
#19 - gerthc (02/28/2012) [+] (1 reply)
2 sqrt(-abs(abs(x)-1)*abs(3-abs(x))/((abs(x)-1)*(3-abs(x))))(1+abs(abs(x)-3)/(abs( x)-3))sqrt(1-(x/7)^2)+(5+0.97(abs(x-.5)+abs(x+.5))-3(abs(x-.75)+abs(x+.75)))(1+a bs(1-abs(x))/(1-abs(x))),-3sqrt(1-(x/7)^2)sqrt(abs(abs(x)-4)/(abs(x)-4)),abs(x/2 )-0.0913722(x^2)-3+sqrt(1-(abs(abs(x)-2)-1)^2),(2.71052+(1.5-.5abs(x))-1.35526sq rt(4-(abs(x)-1)^2))sqrt(abs(abs(x)-1)/(abs(x)-1))+0.9

Simply type this in google search bar...
#35 - zigzagderpaderp (02/28/2012) [+] (1 reply)
OH MY GOD, I have to do this project for calculus where we use an enclosed region on a graph and find the area of the figure with shapes on top (pic somewhat related), this is PERFECT

In the event that this doesn't work, anyone have suggestions for other shapes?
inb4 dickbutt or penis
#30 - anonimis (02/28/2012) [-]
Did I do that?
+2
#4 - captaincabinet **User deleted account** has deleted their comment [-]
0
#28 - russianak has deleted their comment [-]
#25 - studlymcstud (02/28/2012) [-]
**studlymcstud rolled a random image posted in comment #890 at lol wut **
#14 - anonymous (02/28/2012) [-]
**anonymous rolled a random image posted in comment #8 at CROSS BOW! (Description, check it) **
#9 - anonymous (02/27/2012) [-]
next year im in this class FML
#8 - runinplace (02/27/2012) [+] (3 replies)
**runinplace rolls 281**
0
#13 to #8 - Eydrrup has deleted their comment [-]
#5 - feragon ONLINE (02/27/2012) [+] (1 reply)
I very much doubt that this is possible without having assymptotes/limits
User avatar #3 - abraxocleaner (02/27/2012) [-]
**** man in grade 11 im gonna have to take functions and somehow puul of that **** fml
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