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#57

squidyj (09/22/2011) []
n
2n
2n + 5
50 * (2n + 5) = 100n + 250
100n + 2011  100n + 2010
100n + 2011  m  100n + 2010  m
100n + 2011  m  100n + 2011  m  1
age = current year  birth year. if birthday has not occurred, subtract 1
100n + age  100n + age
OH MY GOD BASIC ARITHMETIC, SO CLEVER.
n
2n
2n + 5
50 * (2n + 5) = 100n + 250
100n + 2011  100n + 2010
100n + 2011  m  100n + 2010  m
100n + 2011  m  100n + 2011  m  1
age = current year  birth year. if birthday has not occurred, subtract 1
100n + age  100n + age
OH MY GOD BASIC ARITHMETIC, SO CLEVER.
#754

lodisboeg (09/22/2011) [] Math Trick Explained (The Math Behind it, and how and why it works)
Ok, this is not going to amuse everyone I know, but I write it for those who might find it interesting. I'll try to explain why each step is done.
Ok, first of we pick our 'sex per week number', call it x.
We then multiply it with 2, so we get 2x.
Next, we add 5, so we get 2x+5, which we multiply with 50, so (2x+5)*50=100x+250
We then add 1761 (or 1760, if you havent had your birthday yet. Why will be pretty clear soon), which gives us 100x+2011(I'm guessing you can see where this is going...:3) and we then subtract our birth year, say y. This gives us 100x+2011y. So say I want to **** 3 times a week, thats x=3, so 300+ 2011y, say that I'm born 1992, and have had my birthday, thats 19. When we add these togheter we get 319, which is the number I would have gotten if I had done all the written steps also.
So, all in all we just multiply our 'sexnumber' with 100 to get it to the first position, and then we add 2011 our birth year, which is our age, which unless you are over 100 years old, will have two digits and so end up behind our 'sexnumber'.
There you have it, FJ:3 Hope you found it interesting.
Now back to college calculusstudies:)
Ok, this is not going to amuse everyone I know, but I write it for those who might find it interesting. I'll try to explain why each step is done.
Ok, first of we pick our 'sex per week number', call it x.
We then multiply it with 2, so we get 2x.
Next, we add 5, so we get 2x+5, which we multiply with 50, so (2x+5)*50=100x+250
We then add 1761 (or 1760, if you havent had your birthday yet. Why will be pretty clear soon), which gives us 100x+2011(I'm guessing you can see where this is going...:3) and we then subtract our birth year, say y. This gives us 100x+2011y. So say I want to **** 3 times a week, thats x=3, so 300+ 2011y, say that I'm born 1992, and have had my birthday, thats 19. When we add these togheter we get 319, which is the number I would have gotten if I had done all the written steps also.
So, all in all we just multiply our 'sexnumber' with 100 to get it to the first position, and then we add 2011 our birth year, which is our age, which unless you are over 100 years old, will have two digits and so end up behind our 'sexnumber'.
There you have it, FJ:3 Hope you found it interesting.
Now back to college calculusstudies:)
#107

jesterif (09/22/2011) []
Let me explain how this works.
Let x be the desired number of le sexy times.
2x
2x+50
100x + 250 + 1670 + 1 if birthday passed = 100x + 2010 (or 2011 if birthday passed)
What happens if you substract the year you were born from 2010 (or 2011 if birthday passed)? Gives you your age. And why is the first digit is x? Well, x is multiplied by 100, thus the number is x00 + age = x(age). Yes, I was bored.
Let x be the desired number of le sexy times.
2x
2x+50
100x + 250 + 1670 + 1 if birthday passed = 100x + 2010 (or 2011 if birthday passed)
What happens if you substract the year you were born from 2010 (or 2011 if birthday passed)? Gives you your age. And why is the first digit is x? Well, x is multiplied by 100, thus the number is x00 + age = x(age). Yes, I was bored.