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#119

exploiterguyone (01/14/2013) []
There is a 10% chance of getting dubs, if the algorithm is perfectly random.
I have a feeling that the algorithm is not perfectly random.
I have a feeling that the algorithm is not perfectly random.
#132 to #119

exploiterguyone (01/14/2013) []
After 10 rolls have been completed, 2 of them are dubs. If there is a 10% chance of dubs occurring, than the formula for deciding the chances of this happening is:
(.1)^2 x (.9)^8
= .00434
since there is a .43% chance of complete randomness resulting in 2 dubs out of 10 tries, It is reasonable to believe that the algorithm is not random, and is seeded to have an artificially large number of dubs.
(.1)^2 x (.9)^8
= .00434
since there is a .43% chance of complete randomness resulting in 2 dubs out of 10 tries, It is reasonable to believe that the algorithm is not random, and is seeded to have an artificially large number of dubs.
#161 to #132

swordguyoxd (01/14/2013) []
look up the definition of algorithm
Then tell me what "the" you're referencing cause all I see here is a formula
Then tell me what "the" you're referencing cause all I see here is a formula
#298 to #161

exploiterguyone (01/14/2013) []
The algorithm FJ uses to produce "random" numbers.
Algorithm, n:
a stepbystep procedure for solving a problem or accomplishing some end, especially by a computer
I refer to the code FJ's staff has written that produces integers. I have shown through statistical analysis that the algorithm is probably not random, and thus is seeded to produce an artificially high amount of doubles. I never said I was referring to my formula when I said algorithm, and i wasn't. You thumbed me down because you didn't understand the math I was using? spectacular.
Algorithm, n:
a stepbystep procedure for solving a problem or accomplishing some end, especially by a computer
I refer to the code FJ's staff has written that produces integers. I have shown through statistical analysis that the algorithm is probably not random, and thus is seeded to produce an artificially high amount of doubles. I never said I was referring to my formula when I said algorithm, and i wasn't. You thumbed me down because you didn't understand the math I was using? spectacular.
#133 to #132

exploiterguyone (01/14/2013) []
the chance of 3/11 is
.1^3 x .9^8
.00043
.043% chance
Definitely seeded.
.1^3 x .9^8
.00043
.043% chance
Definitely seeded.