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Comments(262):
What do you think? Give us your opinion. Anonymous comments allowed.
#51

whatley (08/06/2012) []
Old myth, let me disprove this with maths.
cdn.bulbagarden.net/upload/2/20/Catch_formula_1.png
This is the formula used for calculating the catch rate of a Pokemon. Just to be nice to you, I'll pick the mathematically hardest Pokemon to catch, Mewtwo. Taking his base stats off of the internet and assuming his health is full, "HP current" should equal 106 along with "HP max".
Mewtwo's catch rate is three, like most legendaries (Which is why they're so hard to catch), so "Rate" is 3.
Also assuming he has no status on him (Like sleep or paralysis) the "BONUSstatus" is one and the BONUSball for the Master ball is 255, plug that all into the formula and you get a=255.
Now, the second formula we need to use is this,
cdn.bulbagarden.net/upload/7/7e/Catch_formula_2.png
This formula will give us the "shake probability". Each time the pokeball wobbles it performs a test, to see if the value of "a" is high enough for the pokemon to be caught, if it isn't, then it'll break free. For each of these tests, a random number between 0 and 65535 is generated and tested against the value of "b" that is derived from this new formula. If "b" is higher than or equal to the random number, then that test is passed, if all four tests are passed, then you catch the Pokemon ( **** yeah).
Now, our value for "a" was 255, so if you stick it into that formula then the value that you'll get for "b" is 65535, and the very highest value that can be generated is, guess what, 65535. And if "b" is higher than or equal to the number generated, then you pass the tests. Therefore b will always be greater than or equal to the number generated, so you CANNOT fail if you use a Master ball. QED.
tl;dr  Maths says that you can't fail using a Master ball, so happy legendary catchings.
cdn.bulbagarden.net/upload/2/20/Catch_formula_1.png
This is the formula used for calculating the catch rate of a Pokemon. Just to be nice to you, I'll pick the mathematically hardest Pokemon to catch, Mewtwo. Taking his base stats off of the internet and assuming his health is full, "HP current" should equal 106 along with "HP max".
Mewtwo's catch rate is three, like most legendaries (Which is why they're so hard to catch), so "Rate" is 3.
Also assuming he has no status on him (Like sleep or paralysis) the "BONUSstatus" is one and the BONUSball for the Master ball is 255, plug that all into the formula and you get a=255.
Now, the second formula we need to use is this,
cdn.bulbagarden.net/upload/7/7e/Catch_formula_2.png
This formula will give us the "shake probability". Each time the pokeball wobbles it performs a test, to see if the value of "a" is high enough for the pokemon to be caught, if it isn't, then it'll break free. For each of these tests, a random number between 0 and 65535 is generated and tested against the value of "b" that is derived from this new formula. If "b" is higher than or equal to the random number, then that test is passed, if all four tests are passed, then you catch the Pokemon ( **** yeah).
Now, our value for "a" was 255, so if you stick it into that formula then the value that you'll get for "b" is 65535, and the very highest value that can be generated is, guess what, 65535. And if "b" is higher than or equal to the number generated, then you pass the tests. Therefore b will always be greater than or equal to the number generated, so you CANNOT fail if you use a Master ball. QED.
tl;dr  Maths says that you can't fail using a Master ball, so happy legendary catchings.
#159 to #51

aBlindMoron (08/07/2012) []
Oh cool, a mathematician.
Ever heard that rumor that a high level of concentration on something can affect a RNG?
What if all that time I spent pressing B while the Pokeball shook affected the RNG and raised the value of b?
What if pressing B actually did make a catch more likely?
What if I was phone?
Ever heard that rumor that a high level of concentration on something can affect a RNG?
What if all that time I spent pressing B while the Pokeball shook affected the RNG and raised the value of b?
What if pressing B actually did make a catch more likely?
What if I was phone?
#129 to #51

ultiomos (08/06/2012) []
And, when a Master Ball is used, it skips the catch formula, anyways. So even a Pokémon with a catch rate of 0 would be caught, even though it wouldn't if the formula was used. I've done a little bit of ROM hacking, and messed around with this before, so I've got experience.
#48

shadowsynergy ONLINE (08/06/2012) []
I never use my masterball. I love the long grueling boss battles and spamming pokeballs...
#46

guiguito ONLINE (08/06/2012) []
playing pokemon gold on a emulator
trying to catch entei
the ball never worked
trying to catch entei
the ball never worked
#44

simplelife (08/06/2012) []
Yeah it's happened to me in pokemon yellow trying to catch mewtwo. It was a bad day indeed.
#38

mushimeister (08/06/2012) []
I don't even need to save before catching mewtwo, I have the masterball. ****
#37

anonymous (08/06/2012) []
Imagine being that poor sod..............." Ya I caught mewtwo!!!!...................wait you've gotta be ******* kidding me!!!!!!!!!!
#32

hertogrick (08/06/2012) []
If you're using the master ball it means it's probably a legendary you're catching. You should always save before going to battle with a legendary. No worries about the odds.
#29

celestiasbeard (08/06/2012) []
pokemon have a very weird equation equaling the catch rate with the highest being 255 which is near impossible to catch or even see, a masterball and two other pokeballs have a set value of 255 so they cant **** up
#28

subjectomega (08/06/2012) []
did you know that sonic first appeared as an air freshener in the racing game Rad Mobile?
#25

anonymous (08/06/2012) []
This is actually false. Since red and blue, the master ball has had a script in which the game goes "oh he is using a master ball, instant catch". The master ball thus catches anything (with the exception of the marowak in the pokemon tower in firered/leafgreen, he has a catchrate of 0 an is uncatchable.)