Rated M for math. .
x

Comments(113):

[ 113 comments ]
What do you think? Give us your opinion. Anonymous comments allowed.
#34 - zenith (12/26/2013) [-]
0
User avatar #55 to #34 - runescapewasgood (12/26/2013) [-]
sauce? I seem to remember something about it from FJ but don't know where it's from.
#60 to #55 - kangster (12/26/2013) [-]
Aiiight listen to this:
X goes to 5, which meansit goes to (2e^(5 - 5) - 2) / 5 - 4
= (2e^0 - 2) / 1 = (2 * 1 - 2) / 1 = (2 - 2) / 1 = 0 / 1 = 0
User avatar #56 to #55 - settantaventi (12/26/2013) [-]
Drawn Together: Suicide Hotline - Commercial Drawn Together
User avatar #68 to #34 - bruinslover (12/26/2013) [-]
got Season 3 for Christmas.
User avatar #62 - AlbertEinstein (12/26/2013) [-]
The answer is 0.
That has to be one of the easiest limit problems I've seen in my entire life
User avatar #75 to #62 - dopeydoo (12/26/2013) [-]
well, try doing it as a elementary school child who still plays math blaster
+8
#76 to #62 - iviagic has deleted their comment [-]
User avatar #93 - EnemySpy (12/27/2013) [-]
Oh dang, look at all these professional mathematicians we got here on FJ.
Are you impressed? I am impressed.
#100 to #93 - anon (12/27/2013) [-]
WOOOOOOOOOO!
WOOOOOOOOOO!
#101 to #100 - neurofuzzy (12/27/2013) [-]
forgot to log in.    
   
 UNLIMITED POWER!!
forgot to log in.

UNLIMITED POWER!!
#89 - anon (12/26/2013) [-]
puttin' x-5 instead of x-4 in the denominator would have ****** it up just right
#96 to #89 - garnykins (12/27/2013) [-]
But then we just apply L'Hôpital's rule. Life is fixed.
#99 to #96 - anon (12/27/2013) [-]
LOS HOSPITALS RULE IS THE SOLUTION TO LIFE AND ALL OF ITS MYSTERIES
#27 - micekill (12/26/2013) [-]
answah is 0
brathers
#31 to #27 - joekerr (12/26/2013) [-]
It's actually sin (π).
It's actually sin (π).
User avatar #40 to #31 - SaugusCent (12/26/2013) [-]
And Sin of pie is 0
User avatar #46 to #40 - angreif (12/26/2013) [-]
preeeeetty sure that he was making a joke
#61 to #40 - joekerr (12/26/2013) [-]
Not sure if christmas joke ... or kidding.
User avatar #10 - thechosentroll (12/26/2013) [-]
Come on, it's not even hard for a lim equation. It's 0.
#104 to #10 - anon (12/27/2013) [-]
You need to learn about basic mathematics first mate I dint know you could run before you walked
User avatar #106 to #104 - thechosentroll (12/27/2013) [-]
I learned this **** in the 10th grade.
#11 to #10 - Eralus (12/26/2013) [-]
Comment Picture
User avatar #42 to #11 - xnaitomea (12/26/2013) [-]
i remember when this gif was used a lot...
User avatar #39 - yunoknow (12/26/2013) [-]
man this was the **** back when i was having computer classes in elementary school... do kids these days even need computer classes?
#45 to #39 - wolviewolverine (12/26/2013) [-]
This image has expired
We have desk classes sometimes.
A good relief from our computer based everyday classes, I say.
User avatar #97 to #45 - yunoknow (12/27/2013) [-]
damn i feel old
#12 - beasert (12/26/2013) [-]
Heck yeah! Math Blaster!
Heck yeah! Math Blaster!
User avatar #26 to #12 - Znoflats (12/26/2013) [-]
I loved this when I was a kid! I barely knew what math was, I only typed in random numbers. WHERE CAN I FIND IT!?
#86 - szymonf (12/26/2013) [-]
Comment Picture
#71 - darkangelmeanya (12/26/2013) [-]
Here's a template if anyone wants it...
User avatar #18 - nthmetal (12/26/2013) [-]
you could have made it lim x->4 to make it a tiny bit harder.
#29 to #18 - anon (12/26/2013) [-]
It would make it easier actually, since (anything*)/0 is infinity.

*except 0 and infinity
#30 to #29 - nthmetal (12/26/2013) [-]
You better be trolling son.
You better be trolling son.
#33 to #30 - musicman (12/26/2013) [-]
are you stupid
#36 to #33 - nthmetal (12/26/2013) [-]
Anything/0 is undefined. ANYTHING.
0/0 is undefined. ∞/0 is undefined. (-∞,∞)/0 is undefined.
Anon said anything/0 is infinity, now I'm assuming he meant in the context of limits because he'd be even more wrong otherwise.
Lets take a simple limit, the one in the picture. If we attempt to solve it by pluging in we can see that we get 1/0, which means the limit DOES NOT EXIST
However, we can take the left hand limit and get that it equals -∞ or the right hand limit and it equals ∞. However we can't take the regular limit because it does not exist.
Now does not existing equal infinity as annon said? NO it doesn't.

The same applies to the limit on the monster. If we were to replace it with as x→4 instead of x→5 it would have no solution if you attempted to take the limit.

Do you understand now you ignorant twat.
#38 to #36 - musicman (12/26/2013) [-]
so no, the number never truely reach 0 or in your pictures case 1.
In the case of your picture as the limit approaches 1 you can pick a number .9999999999 which is almost 1 but never reaches 1.
1/(1-.9999999999)
1/(.0000000001) or 1000000000/1 and from the left it is -1000000000 and so forth

Now, how do we tell whether it's ∞, −∞, or neither? Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim x−4
x→3+ x−3 X→−∞
User avatar #49 to #38 - nthmetal (12/26/2013) [-]
"Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim x−4
x→3+ x−3 X→−∞"

Dude what the **** are you trying to say. I read this and I can't even understand what the hell you're doing or where the hell these numbers came from. Like where the hell did you get x→3+, Either of the cases we have been discussing so far are either x→1, x→4, and x→5.
"x→3+ x−3 X→−∞" what the hell kind of ******** is this. Where did this second "X" variable come from, I thought we were only using x, and how the hell can x approach 3+x-3X and how can that approach -infinity.
Buddy learn how to write math. Use a picture, jot it down legibly on a piece of paper. Pretend i'm a 5 year old if that helps you learn to write better.


Either way I don't know what the hell it is you're trying to argue, but all I know is that i'm not wrong. Anon said that the limit as x approaches 4 of the function on the screen will be zero, this implys that any number divided by zero will equal ∞. This is untrue because any number over zero will be undefined.
#107 to #49 - musicman (12/27/2013) [-]
not in terms of limits it is limit as the number approaches the x value the denominator never really reaches 0 but instead gets smaller and smaller. as the denominator gets smaller and the numerator gets bigger the whole expression gets bigger
User avatar #110 to #107 - nthmetal (12/27/2013) [-]
Limits are only valid if the left hand limit is equal to the right hand limit. In both cases they are not, so the answer is undefined.
User avatar #72 to #36 - zecken (12/26/2013) [-]
you propably never heard of Bernoulli and l'Hospital. lets say you have an equtation which would result in 0/0 it doesn t have to be undefined. lets say lim x->0 x²/x. this would be undefined in your case so but now we can, because of bernoulli, make a derviation which leaves us with lim x->0 2x/1 put in 0 and you got 0/1 which is Infinity, You will find a lot of cases where you can use Bernoulli. Sorry for my English...
User avatar #111 to #72 - nthmetal (12/27/2013) [-]
lim x->0 2x/1 put in 0 and you got 0/1 which is Infinity,

0/1 equals 0 not infinity
#43 to #29 - pettdavids (12/26/2013) [-]
note that when (anything) / 0 = ∞, then 0 * ∞ = (anything), which doesn't make sense. Therefore we say zero times infinity is undefined, and therefore anything divided by zero is undefined
User avatar #35 to #29 - BruisingPrune (12/26/2013) [-]
anything/0 is undefined/does not exist.

the whole dividing by 0 thing
+7
#77 - iviagic has deleted their comment [-]
#81 to #77 - cornflakekiller (12/26/2013) [-]
To the Bandwagon
User avatar #78 to #77 - hornack (12/26/2013) [-]
Troll? Automatic thumb up
+9
#79 to #78 - iviagic has deleted their comment [-]
User avatar #80 to #79 - hornack (12/26/2013) [-]
So? I'll help you get there by thumbing you up.
+5
#82 to #80 - iviagic has deleted their comment [-]
User avatar #85 to #82 - Leopard (12/26/2013) [-]
Then have this thumb

You'll need a lot if you're at level -300 something.
User avatar #1 - rubiksdodecahedron (12/26/2013) [-]
what's lim?
User avatar #21 to #1 - naitsabesh ONLINE (12/26/2013) [-]
Norwegian for glue.
#2 to #1 - xolotyl **User deleted account** (12/26/2013) [-]
It means take the limit, or what answer the equation goes to as it approaches the value of x. In this case the answer is zero since as x goes to 5, (2e^x - 2)/(x-4) goes to (2-2)/(5-1) = 0/1 = 0.
#9 to #2 - hallazabassist ONLINE (12/26/2013) [-]
Yup, it's 0.
User avatar #5 to #2 - respectyourmom (12/26/2013) [-]
you seem pretty smart so can you please explain why all that confusing math is necessary to know in life? what exact profession would use those types of equations, so i can stay faaaarrrr away from them...
User avatar #6 to #5 - xolotyl **User deleted account** (12/26/2013) [-]
Well this stuff is actually just basic calculus and is pretty much just used to be able to better understand more complex calculus. This stuff specifically should be covered towards the end of high school. If you want to stay away from math then you probably want to avoid careers in the hard sciences (like physics, chemistry, biology, and engineering) and computer science.
User avatar #8 to #6 - respectyourmom (12/26/2013) [-]
well thank you
User avatar #32 to #8 - brnoflynn (12/26/2013) [-]
Or alternatively try and learn and understand it and stop limiting yourself (pun not intended) before you even begin...
#23 to #5 - anon (12/26/2013) [-]
You can also throw complex coding out of the window
User avatar #3 to #2 - xolotyl **User deleted account** (12/26/2013) [-]
Sorry it should be 2e^(x-5)-2 like above, I wrote it down wrong here but still solved it the right way
User avatar #4 to #3 - rubiksdodecahedron (12/26/2013) [-]
ok thanks
#103 to #2 - anon (12/27/2013) [-]
Comment Picture
User avatar #57 to #2 - advicedude (12/26/2013) [-]
So like a loop in code?
User avatar #108 to #57 - xolotyl **User deleted account** (12/27/2013) [-]
I'm not sure about that, I haven't really studied programming.
User avatar #112 to #108 - advicedude (12/27/2013) [-]
A group of code is run until a variable reaches a certain value.

e.x. Until x is equal to 5, run code

Code: x + 1
User avatar #113 to #112 - xolotyl **User deleted account** (12/27/2013) [-]
Oh ok, yeah that's not really the same as the math here. Limits are used to determine specific values of discontinuous functions, and to define derivatives/integrals.
User avatar #64 to #57 - bookyle (12/26/2013) [-]
no, it's calc. Nothing to do with cs
#54 to #2 - unholyjebus (12/26/2013) [-]
MFW I have Dyscalculia.
User avatar #109 to #54 - xolotyl **User deleted account** (12/27/2013) [-]
At least you don't have lysdexia
#53 to #2 - AZNRULEZ (12/26/2013) [-]
damn it, I solved it and was going to post the answer to thumb whore....And yes, I'm asian, look at my username
#50 - comicsjoey **User deleted account** (12/26/2013) [-]
**comicsjoey rolls 52** this is from the last time this was posted
User avatar #58 to #50 - imagnetsux (12/26/2013) [-]
**imagnetsux rolls 24**
#59 to #58 - comicsjoey **User deleted account** (12/26/2013) [-]
User avatar #70 to #50 - sackit (12/26/2013) [-]
**sackit rolls 87** ******* casuals
User avatar #84 to #50 - warzon (12/26/2013) [-]
**warzon rolls 63**

But what happens if we do roll dubs.
User avatar #88 to #50 - neoexdeath (12/26/2013) [-]
**neoexdeath rolls 16**
#102 to #50 - anon (12/27/2013) [-]
**anonymous rolls 66**
#105 to #102 - anon (12/27/2013) [-]
Yes!
#51 to #50 - comicsjoey **User deleted account** (12/26/2013) [-]
#67 - zomaru (12/26/2013) [-]
Numbers were never my thing...
#69 - knarket (12/26/2013) [-]
isn't it supposed to be "x - 5" in the denominator? now it's just the oddest limit..
#73 to #69 - fasde (12/26/2013) [-]
no
#95 - asstraffic (12/27/2013) [-]
HEY GUYS! THE ANSWER IS 0!
HEY GUYS! THE ANSWER IS 0!
#52 - pineapplepeople (12/26/2013) [-]
I love these math related contents so I can scroll down and see all the people trying to show off their knowledge (and half of them fail).
#25 - anon (12/26/2013) [-]
Why the **** would you use lim for that equation? lim x->5 and x=5 would give the same answer here. Lim isn't use like this.
#28 to #25 - anon (12/26/2013) [-]
Obviously it isn't an important spot to take a limit, because nothing weird is going on. It's just continuous through the limit. But the fact that a limit problem is on "math blaster" meant for kids makes it rough.
#91 - anon (12/26/2013) [-]
who cares? You dumb ***** kept red thumbing orstick today (wonder why I spelled his name wrong) and he got dark lord status. Gullible pieces of **** . lol.

And to think, you call cry and whine when anyone else does it. Now worship him, you lemming ********* .
User avatar #92 to #91 - hahahaheidi (12/26/2013) [-]
Could you not
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