It means take the limit, or what answer the equation goes to as it approaches the value of x. In this case the answer is zero since as x goes to 5, (2e^x - 2)/(x-4) goes to (2-2)/(5-1) = 0/1 = 0.
you seem pretty smart so can you please explain why all that confusing math is necessary to know in life? what exact profession would use those types of equations, so i can stay faaaarrrr away from them...
Well this stuff is actually just basic calculus and is pretty much just used to be able to better understand more complex calculus. This stuff specifically should be covered towards the end of high school. If you want to stay away from math then you probably want to avoid careers in the hard sciences (like physics, chemistry, biology, and engineering) and computer science.
Oh ok, yeah that's not really the same as the math here. Limits are used to determine specific values of discontinuous functions, and to define derivatives/integrals.
Anything/0 is undefined. ANYTHING.
0/0 is undefined. âˆž/0 is undefined. (-âˆž,âˆž)/0 is undefined.
Anon said anything/0 is infinity, now I'm assuming he meant in the context of limits because he'd be even more wrong otherwise.
Lets take a simple limit, the one in the picture. If we attempt to solve it by pluging in we can see that we get 1/0, which means the limit DOES NOT EXIST
However, we can take the left hand limit and get that it equals -âˆž or the right hand limit and it equals âˆž. However we can't take the regular limit because it does not exist.
Now does not existing equal infinity as annon said? NO it doesn't.
The same applies to the limit on the monster. If we were to replace it with as xâ†’4 instead of xâ†’5 it would have no solution if you attempted to take the limit.
you propably never heard of Bernoulli and l'Hospital. lets say you have an equtation which would result in 0/0 it doesn t have to be undefined. lets say lim x->0 xÂ²/x. this would be undefined in your case so but now we can, because of bernoulli, make a derviation which leaves us with lim x->0 2x/1 put in 0 and you got 0/1 which is Infinity, You will find a lot of cases where you can use Bernoulli. Sorry for my English...
so no, the number never truely reach 0 or in your pictures case 1.
In the case of your picture as the limit approaches 1 you can pick a number .9999999999 which is almost 1 but never reaches 1.
1/(1-.9999999999)
1/(.0000000001) or 1000000000/1 and from the left it is -1000000000 and so forth
Now, how do we tell whether it's âˆž, âˆ’âˆž, or neither? Well, the numerator of the fraction is getting close to âˆ’1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as xâ†’3+, x>3, so xâˆ’3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim xâˆ’4
xâ†’3+ xâˆ’3 Xâ†’âˆ’âˆž
"Well, the numerator of the fraction is getting close to âˆ’1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as xâ†’3+, x>3, so xâˆ’3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim xâˆ’4
xâ†’3+ xâˆ’3 Xâ†’âˆ’âˆž"
Dude what the **** are you trying to say. I read this and I can't even understand what the hell you're doing or where the hell these numbers came from. Like where the hell did you get xâ†’3+, Either of the cases we have been discussing so far are either xâ†’1, xâ†’4, and xâ†’5.
"xâ†’3+ xâˆ’3 Xâ†’âˆ’âˆž" what the hell kind of ******** is this. Where did this second "X" variable come from, I thought we were only using x, and how the hell can x approach 3+x-3X and how can that approach -infinity.
Buddy learn how to write math. Use a picture, jot it down legibly on a piece of paper. Pretend i'm a 5 year old if that helps you learn to write better.
Either way I don't know what the hell it is you're trying to argue, but all I know is that i'm not wrong. Anon said that the limit as x approaches 4 of the function on the screen will be zero, this implys that any number divided by zero will equal âˆž. This is untrue because any number over zero will be undefined.
not in terms of limits it is limit as the number approaches the x value the denominator never really reaches 0 but instead gets smaller and smaller. as the denominator gets smaller and the numerator gets bigger the whole expression gets bigger
note that when (anything) / 0 = âˆž, then 0 * âˆž = (anything), which doesn't make sense. Therefore we say zero times infinity is undefined, and therefore anything divided by zero is undefined
who cares? You dumb ***** kept red thumbing orstick today (wonder why I spelled his name wrong) and he got dark lord status. Gullible pieces of **** . lol.
And to think, you call cry and whine when anyone else does it. Now worship him, you lemming ********* .