Rated M for math. . Rated M for math
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#10 - thechosentroll
Reply +36
(12/26/2013) [-]
Come on, it's not even hard for a lim equation. It's 0.
#104 to #10 - anon
Reply 0
(12/27/2013) [-]
You need to learn about basic mathematics first mate I dint know you could run before you walked
#106 to #104 - thechosentroll
Reply -1
(12/27/2013) [-]
I learned this **** in the 10th grade.
#11 to #10 - Eralus ONLINE
Reply +94
(12/26/2013) [-]
Comment Picture
#42 to #11 - xnaitomea
Reply +2
(12/26/2013) [-]
i remember when this gif was used a lot...
#1 - rubiksdodecahedron
Reply +4
(12/26/2013) [-]
what's lim?
#21 to #1 - naitsabesh
Reply +4
(12/26/2013) [-]
Norwegian for glue.
#2 to #1 - xolotyl **User deleted account**
Reply +88
(12/26/2013) [-]
It means take the limit, or what answer the equation goes to as it approaches the value of x. In this case the answer is zero since as x goes to 5, (2e^x - 2)/(x-4) goes to (2-2)/(5-1) = 0/1 = 0.
#9 to #2 - hallazabassist ONLINE
Reply +6
(12/26/2013) [-]
Yup, it's 0.
#5 to #2 - respectyourmom
Reply +1
(12/26/2013) [-]
you seem pretty smart so can you please explain why all that confusing math is necessary to know in life? what exact profession would use those types of equations, so i can stay faaaarrrr away from them...
#6 to #5 - xolotyl **User deleted account**
Reply +5
(12/26/2013) [-]
Well this stuff is actually just basic calculus and is pretty much just used to be able to better understand more complex calculus. This stuff specifically should be covered towards the end of high school. If you want to stay away from math then you probably want to avoid careers in the hard sciences (like physics, chemistry, biology, and engineering) and computer science.
#8 to #6 - respectyourmom
Reply 0
(12/26/2013) [-]
well thank you
#32 to #8 - brnoflynn
Reply +2
(12/26/2013) [-]
Or alternatively try and learn and understand it and stop limiting yourself (pun not intended) before you even begin...
#23 to #5 - anon
Reply 0
(12/26/2013) [-]
You can also throw complex coding out of the window
#3 to #2 - xolotyl **User deleted account**
Reply +1
(12/26/2013) [-]
Sorry it should be 2e^(x-5)-2 like above, I wrote it down wrong here but still solved it the right way
#4 to #3 - rubiksdodecahedron
Reply 0
(12/26/2013) [-]
ok thanks
#103 to #2 - anon
Reply 0
(12/27/2013) [-]
Comment Picture
#57 to #2 - advicedude
Reply 0
(12/26/2013) [-]
So like a loop in code?
#108 to #57 - xolotyl **User deleted account**
Reply 0
(12/27/2013) [-]
I'm not sure about that, I haven't really studied programming.
#112 to #108 - advicedude
Reply 0
(12/27/2013) [-]
A group of code is run until a variable reaches a certain value.

e.x. Until x is equal to 5, run code

Code: x + 1
#113 to #112 - xolotyl **User deleted account**
Reply 0
(12/27/2013) [-]
Oh ok, yeah that's not really the same as the math here. Limits are used to determine specific values of discontinuous functions, and to define derivatives/integrals.
#64 to #57 - bookyle
Reply 0
(12/26/2013) [-]
no, it's calc. Nothing to do with cs
#54 to #2 - unholyjebus
Reply 0
(12/26/2013) [-]
MFW I have Dyscalculia.
#109 to #54 - xolotyl **User deleted account**
Reply 0
(12/27/2013) [-]
At least you don't have lysdexia
#53 to #2 - AZNRULEZ
Reply 0
(12/26/2013) [-]
damn it, I solved it and was going to post the answer to thumb whore....And yes, I'm asian, look at my username
#34 - zenith
Reply +60
(12/26/2013) [-]
0
#55 to #34 - runescapewasgood ONLINE
Reply 0
(12/26/2013) [-]
sauce? I seem to remember something about it from FJ but don't know where it's from.
#60 to #55 - kangster
Reply 0
(12/26/2013) [-]
Aiiight listen to this:
X goes to 5, which meansit goes to (2e^(5 - 5) - 2) / 5 - 4
= (2e^0 - 2) / 1 = (2 * 1 - 2) / 1 = (2 - 2) / 1 = 0 / 1 = 0
#56 to #55 - settantaventi
Reply 0
(12/26/2013) [-]
Drawn Together: Suicide Hotline - Commercial Drawn Together
#68 to #34 - bruinslover
Reply 0
(12/26/2013) [-]
got Season 3 for Christmas.
#62 - AlbertEinstein
Reply +21
(12/26/2013) [-]
The answer is 0.
That has to be one of the easiest limit problems I've seen in my entire life
#75 to #62 - dopeydoo
Reply +1
(12/26/2013) [-]
well, try doing it as a elementary school child who still plays math blaster
#76 to #62 - iviagic
+8
has deleted their comment [-]
#16 - sloot
Reply -8
(12/26/2013) [-]
(2e^5-5) - 2/5-4=
2e^0-2/1=
(2*2) - 2=
#17 to #16 - sloot
Reply -8
(12/26/2013) [-]
=2
#19 to #17 - hvacian
Reply +16
(12/26/2013) [-]
um
ans=(2*e^0-2)/1
ans=2*1-2
ans=2-2
ans=0
#24 to #17 - lolchris
Reply +3
(12/26/2013) [-]
do you even math bro?
#27 - micekill
Reply +13
(12/26/2013) [-]
answah is 0
brathers
#31 to #27 - joekerr
Reply -13
(12/26/2013) [-]
It's actually sin (π).
It's actually sin (π).
#40 to #31 - SaugusCent ONLINE
Reply -2
(12/26/2013) [-]
And Sin of pie is 0
#46 to #40 - angreif ONLINE
Reply +3
(12/26/2013) [-]
preeeeetty sure that he was making a joke
#61 to #40 - joekerr
Reply 0
(12/26/2013) [-]
Not sure if christmas joke ... or kidding.
#93 - EnemySpy ONLINE
Reply +10
(12/27/2013) [-]
Oh dang, look at all these professional mathematicians we got here on FJ.
Are you impressed? I am impressed.
#100 to #93 - anon
Reply 0
(12/27/2013) [-]
WOOOOOOOOOO!
WOOOOOOOOOO!
#101 to #100 - neurofuzzy
Reply 0
(12/27/2013) [-]
forgot to log in.    
   
 UNLIMITED POWER!!
forgot to log in.

UNLIMITED POWER!!
#50 - comicsjoey **User deleted account**
Reply +3
(12/26/2013) [-]
**comicsjoey rolls 52** this is from the last time this was posted
#58 to #50 - imagnetsux
Reply 0
(12/26/2013) [-]
**imagnetsux rolls 24**
#59 to #58 - comicsjoey **User deleted account**
Reply +4
(12/26/2013) [-]
#70 to #50 - sackit
Reply 0
(12/26/2013) [-]
**sackit rolls 87** ******* casuals
#84 to #50 - warzon
Reply 0
(12/26/2013) [-]
**warzon rolls 63**

But what happens if we do roll dubs.
#88 to #50 - neoexdeath ONLINE
Reply 0
(12/26/2013) [-]
**neoexdeath rolls 16**
#102 to #50 - anon
Reply 0
(12/27/2013) [-]
**anonymous rolls 66**
#105 to #102 - anon
Reply 0
(12/27/2013) [-]
Yes!
#51 to #50 - comicsjoey **User deleted account**
Reply +10
(12/26/2013) [-]
#77 - iviagic
+7
has deleted their comment [-]
#81 to #77 - cornflakekiller
Reply +1
(12/26/2013) [-]
To the Bandwagon
#78 to #77 - hornack [OP]
Reply +4
(12/26/2013) [-]
Troll? Automatic thumb up
#79 to #78 - iviagic
+9
has deleted their comment [-]
#80 to #79 - hornack [OP]
Reply +1
(12/26/2013) [-]
So? I'll help you get there by thumbing you up.
#82 to #80 - iviagic
+5
has deleted their comment [-]
#85 to #82 - Leopard
Reply 0
(12/26/2013) [-]
Then have this thumb

You'll need a lot if you're at level -300 something.
#18 - nthmetal
Reply +5
(12/26/2013) [-]
you could have made it lim x->4 to make it a tiny bit harder.
#29 to #18 - anon
Reply 0
(12/26/2013) [-]
It would make it easier actually, since (anything*)/0 is infinity.

*except 0 and infinity
#30 to #29 - nthmetal
Reply +3
(12/26/2013) [-]
You better be trolling son.
You better be trolling son.
#33 to #30 - musicman
Reply -5
(12/26/2013) [-]
are you stupid
#36 to #33 - nthmetal
Reply 0
(12/26/2013) [-]
Anything/0 is undefined. ANYTHING.
0/0 is undefined. ∞/0 is undefined. (-∞,∞)/0 is undefined.
Anon said anything/0 is infinity, now I'm assuming he meant in the context of limits because he'd be even more wrong otherwise.
Lets take a simple limit, the one in the picture. If we attempt to solve it by pluging in we can see that we get 1/0, which means the limit DOES NOT EXIST
However, we can take the left hand limit and get that it equals -∞ or the right hand limit and it equals ∞. However we can't take the regular limit because it does not exist.
Now does not existing equal infinity as annon said? NO it doesn't.

The same applies to the limit on the monster. If we were to replace it with as x→4 instead of x→5 it would have no solution if you attempted to take the limit.

Do you understand now you ignorant twat.
#72 to #36 - zecken
Reply 0
(12/26/2013) [-]
you propably never heard of Bernoulli and l'Hospital. lets say you have an equtation which would result in 0/0 it doesn t have to be undefined. lets say lim x->0 x²/x. this would be undefined in your case so but now we can, because of bernoulli, make a derviation which leaves us with lim x->0 2x/1 put in 0 and you got 0/1 which is Infinity, You will find a lot of cases where you can use Bernoulli. Sorry for my English...
#111 to #72 - nthmetal
Reply 0
(12/27/2013) [-]
lim x->0 2x/1 put in 0 and you got 0/1 which is Infinity,

0/1 equals 0 not infinity
#38 to #36 - musicman
Reply 0
(12/26/2013) [-]
so no, the number never truely reach 0 or in your pictures case 1.
In the case of your picture as the limit approaches 1 you can pick a number .9999999999 which is almost 1 but never reaches 1.
1/(1-.9999999999)
1/(.0000000001) or 1000000000/1 and from the left it is -1000000000 and so forth

Now, how do we tell whether it's ∞, −∞, or neither? Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim x−4
x→3+ x−3 X→−∞
#49 to #38 - nthmetal
Reply -1
(12/26/2013) [-]
"Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim x−4
x→3+ x−3 X→−∞"

Dude what the **** are you trying to say. I read this and I can't even understand what the hell you're doing or where the hell these numbers came from. Like where the hell did you get x→3+, Either of the cases we have been discussing so far are either x→1, x→4, and x→5.
"x→3+ x−3 X→−∞" what the hell kind of ******** is this. Where did this second "X" variable come from, I thought we were only using x, and how the hell can x approach 3+x-3X and how can that approach -infinity.
Buddy learn how to write math. Use a picture, jot it down legibly on a piece of paper. Pretend i'm a 5 year old if that helps you learn to write better.


Either way I don't know what the hell it is you're trying to argue, but all I know is that i'm not wrong. Anon said that the limit as x approaches 4 of the function on the screen will be zero, this implys that any number divided by zero will equal ∞. This is untrue because any number over zero will be undefined.
#107 to #49 - musicman
Reply 0
(12/27/2013) [-]
not in terms of limits it is limit as the number approaches the x value the denominator never really reaches 0 but instead gets smaller and smaller. as the denominator gets smaller and the numerator gets bigger the whole expression gets bigger
#110 to #107 - nthmetal
Reply 0
(12/27/2013) [-]
Limits are only valid if the left hand limit is equal to the right hand limit. In both cases they are not, so the answer is undefined.
#43 to #29 - pettdavids
Reply 0
(12/26/2013) [-]
note that when (anything) / 0 = ∞, then 0 * ∞ = (anything), which doesn't make sense. Therefore we say zero times infinity is undefined, and therefore anything divided by zero is undefined
#35 to #29 - BruisingPrune
Reply -1
(12/26/2013) [-]
anything/0 is undefined/does not exist.

the whole dividing by 0 thing