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asd
#10

thechosentroll
Reply +36 123456789123345869
(12/26/2013) [] Come on, it's not even hard for a lim equation. It's 0.
#106 to #104

thechosentroll
Reply 1 123456789123345869
(12/27/2013) [] I learned this **** in the 10th grade.
#5 to #2

respectyourmom
Reply +1 123456789123345869
(12/26/2013) [] you seem pretty smart so can you please explain why all that confusing math is necessary to know in life? what exact profession would use those types of equations, so i can stay faaaarrrr away from them...
#6 to #5

xolotyl **User deleted account**
Reply +5 123456789123345869
(12/26/2013) [] Well this stuff is actually just basic calculus and is pretty much just used to be able to better understand more complex calculus. This stuff specifically should be covered towards the end of high school. If you want to stay away from math then you probably want to avoid careers in the hard sciences (like physics, chemistry, biology, and engineering) and computer science.
#112 to #108

advicedude
Reply 0 123456789123345869
(12/27/2013) [] A group of code is run until a variable reaches a certain value.
e.x. Until x is equal to 5, run code
Code: x + 1
e.x. Until x is equal to 5, run code
Code: x + 1
#55 to #34

runescapewasgood
Reply 0 123456789123345869
(12/26/2013) [] sauce? I seem to remember something about it from FJ but don't know where it's from.
#62

AlbertEinstein
Reply +21 123456789123345869
(12/26/2013) [] The answer is 0.
That has to be one of the easiest limit problems I've seen in my entire life
That has to be one of the easiest limit problems I've seen in my entire life
#93

EnemySpy
Reply +10 123456789123345869
(12/27/2013) [] Oh dang, look at all these professional mathematicians we got here on FJ.
Are you impressed? I am impressed.
Are you impressed? I am impressed.
#101 to #100

neurofuzzy forgot to log in.
UNLIMITED POWER!!
Reply 0 123456789123345869
(12/27/2013) [] UNLIMITED POWER!!
#18

nthmetal
Reply +5 123456789123345869
(12/26/2013) [] you could have made it lim x>4 to make it a tiny bit harder.
#36 to #33

nthmetal
Reply 0 123456789123345869
(12/26/2013) [] Anything/0 is undefined. ANYTHING.
0/0 is undefined. ∞/0 is undefined. (∞,∞)/0 is undefined.
Anon said anything/0 is infinity, now I'm assuming he meant in the context of limits because he'd be even more wrong otherwise.
Lets take a simple limit, the one in the picture. If we attempt to solve it by pluging in we can see that we get 1/0, which means the limit DOES NOT EXIST
However, we can take the left hand limit and get that it equals ∞ or the right hand limit and it equals ∞. However we can't take the regular limit because it does not exist.
Now does not existing equal infinity as annon said? NO it doesn't.
The same applies to the limit on the monster. If we were to replace it with as x→4 instead of x→5 it would have no solution if you attempted to take the limit.
Do you understand now you ignorant twat.
0/0 is undefined. ∞/0 is undefined. (∞,∞)/0 is undefined.
Anon said anything/0 is infinity, now I'm assuming he meant in the context of limits because he'd be even more wrong otherwise.
Lets take a simple limit, the one in the picture. If we attempt to solve it by pluging in we can see that we get 1/0, which means the limit DOES NOT EXIST
However, we can take the left hand limit and get that it equals ∞ or the right hand limit and it equals ∞. However we can't take the regular limit because it does not exist.
Now does not existing equal infinity as annon said? NO it doesn't.
The same applies to the limit on the monster. If we were to replace it with as x→4 instead of x→5 it would have no solution if you attempted to take the limit.
Do you understand now you ignorant twat.
#72 to #36

zecken
Reply 0 123456789123345869
(12/26/2013) [] you propably never heard of Bernoulli and l'Hospital. lets say you have an equtation which would result in 0/0 it doesn t have to be undefined. lets say lim x>0 x²/x. this would be undefined in your case so but now we can, because of bernoulli, make a derviation which leaves us with lim x>0 2x/1 put in 0 and you got 0/1 which is Infinity, You will find a lot of cases where you can use Bernoulli. Sorry for my English...
#38 to #36

musicman
Reply 0 123456789123345869
(12/26/2013) [] so no, the number never truely reach 0 or in your pictures case 1.
In the case of your picture as the limit approaches 1 you can pick a number .9999999999 which is almost 1 but never reaches 1.
1/(1.9999999999)
1/(.0000000001) or 1000000000/1 and from the left it is 1000000000 and so forth
Now, how do we tell whether it's ∞, −∞, or neither? Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim x−4
x→3+ x−3 X→−∞
In the case of your picture as the limit approaches 1 you can pick a number .9999999999 which is almost 1 but never reaches 1.
1/(1.9999999999)
1/(.0000000001) or 1000000000/1 and from the left it is 1000000000 and so forth
Now, how do we tell whether it's ∞, −∞, or neither? Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim x−4
x→3+ x−3 X→−∞
#49 to #38

nthmetal
Reply 1 123456789123345869
(12/26/2013) [] "Well, the numerator of the fraction is getting close to −1, so it's negative. The denominator of the fraction is getting close to zero, but specifically as x→3+, x>3, so x−3>0 and the denominator is positive. The fraction is the quotient of a negative number and a positive number, so it's negative and
lim x−4
x→3+ x−3 X→−∞"
Dude what the **** are you trying to say. I read this and I can't even understand what the hell you're doing or where the hell these numbers came from. Like where the hell did you get x→3+, Either of the cases we have been discussing so far are either x→1, x→4, and x→5.
"x→3+ x−3 X→−∞" what the hell kind of ******** is this. Where did this second "X" variable come from, I thought we were only using x, and how the hell can x approach 3+x3X and how can that approach infinity.
Buddy learn how to write math. Use a picture, jot it down legibly on a piece of paper. Pretend i'm a 5 year old if that helps you learn to write better.
Either way I don't know what the hell it is you're trying to argue, but all I know is that i'm not wrong. Anon said that the limit as x approaches 4 of the function on the screen will be zero, this implys that any number divided by zero will equal ∞. This is untrue because any number over zero will be undefined.
lim x−4
x→3+ x−3 X→−∞"
Dude what the **** are you trying to say. I read this and I can't even understand what the hell you're doing or where the hell these numbers came from. Like where the hell did you get x→3+, Either of the cases we have been discussing so far are either x→1, x→4, and x→5.
"x→3+ x−3 X→−∞" what the hell kind of ******** is this. Where did this second "X" variable come from, I thought we were only using x, and how the hell can x approach 3+x3X and how can that approach infinity.
Buddy learn how to write math. Use a picture, jot it down legibly on a piece of paper. Pretend i'm a 5 year old if that helps you learn to write better.
Either way I don't know what the hell it is you're trying to argue, but all I know is that i'm not wrong. Anon said that the limit as x approaches 4 of the function on the screen will be zero, this implys that any number divided by zero will equal ∞. This is untrue because any number over zero will be undefined.
#107 to #49

musicman
Reply 0 123456789123345869
(12/27/2013) [] not in terms of limits it is limit as the number approaches the x value the denominator never really reaches 0 but instead gets smaller and smaller. as the denominator gets smaller and the numerator gets bigger the whole expression gets bigger
#43 to #29

pettdavids
Reply 0 123456789123345869
(12/26/2013) [] note that when (anything) / 0 = ∞, then 0 * ∞ = (anything), which doesn't make sense. Therefore we say zero times infinity is undefined, and therefore anything divided by zero is undefined
#35 to #29

BruisingPrune
Reply 1 123456789123345869
(12/26/2013) [] anything/0 is undefined/does not exist.
the whole dividing by 0 thing
the whole dividing by 0 thing